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Consider the reaction between sulfur trioxide and

Chapter 8, Problem 62P

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QUESTION:

Consider the reaction between sulfur trioxide and water:

\(\mathrm{SO}_{3}(g)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}(a q)\)

A chemist allows 61.5 g of \(\mathrm{SO}_{3}\) and 11.2 g of \(\mathrm{H}_{2} \mathrm{O}\) to react. When the reaction is finished, the chemist collects 54.9 g of \(\mathrm{H}_{2} \mathrm{SO}_{4}\). Determine the limiting reactant, theoretical yield, and percent yield for the reaction.

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QUESTION:

Consider the reaction between sulfur trioxide and water:

\(\mathrm{SO}_{3}(g)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}(a q)\)

A chemist allows 61.5 g of \(\mathrm{SO}_{3}\) and 11.2 g of \(\mathrm{H}_{2} \mathrm{O}\) to react. When the reaction is finished, the chemist collects 54.9 g of \(\mathrm{H}_{2} \mathrm{SO}_{4}\). Determine the limiting reactant, theoretical yield, and percent yield for the reaction.

ANSWER:

Step 1 of 5

Theoretical yield is the amount of product that can be made in a chemical reaction based on the amount of limiting reactant.

Actual yield is the amount of product actually produced by a chemical reaction.

\(\text { Percent yield }=\frac{\text { actual yield }}{\text { theoretical yield }} \times 100 \%\)

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