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Consider the equation for the combustion of acetone

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 73P Chapter 8

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 73P

PROBLEM 73P

Consider the equation for the combustion of acetone (C3H6O), the main ingredient in nail polish remover:

C3H6O(l) + 4 O2(g) → 3 CO2(g) + 3 H2O(g) ΔHrxn = −1790 kJ

If a bottle of nail polish remover contains 155 g of acetone, how much heat is released by its complete combustion?

Step-by-Step Solution:
Step 1 of 3

Solution 73P

Consider the below equation

C3H6O(l) + 4 O2(g) → 3 CO2(g) + 3 H2O(g) ΔHrxn = −1790 kJ

From the equation it is clear that 1 mole of acetone releases 1790 KJ of energy

Molecular mass of acetone is 123+61+161=58grams

155...

Step 2 of 3

Chapter 8, Problem 73P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

The answer to “Consider the equation for the combustion of acetone (C3H6O), the main ingredient in nail polish remover:C3H6O(l) + 4 O2(g) ? 3 CO2(g) + 3 H2O(g) ?Hrxn = ?1790 kJIf a bottle of nail polish remover contains 155 g of acetone, how much heat is released by its complete combustion?” is broken down into a number of easy to follow steps, and 49 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 73P from chapter: 8 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 73P from 8 chapter was answered, more than 596 students have viewed the full step-by-step answer. This full solution covers the following key subjects: acetone, remover, combustion, polish, nail. This expansive textbook survival guide covers 19 chapters, and 2045 solutions.

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