Solution Found!
Consider the equation for the combustion of acetone (C3H6O), the main ingredient in nail
Chapter 8, Problem 73P(choose chapter or problem)
Consider the equation for the combustion of acetone (\(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\)), the main ingredient in nail polish remover:
\(\begin{array}{r}
\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l)+4 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 3 \mathrm{CO}_{2}(\mathrm{~g})+3 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \\
\Delta H_{\mathrm{rxn}}=-1790 \mathrm{~kJ}
\end{array}\)
If a bottle of nail polish remover contains 155 g of acetone, how much heat is released by its complete combustion?
Questions & Answers
(1 Reviews)
QUESTION:
Consider the equation for the combustion of acetone (\(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\)), the main ingredient in nail polish remover:
\(\begin{array}{r}
\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l)+4 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 3 \mathrm{CO}_{2}(\mathrm{~g})+3 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \\
\Delta H_{\mathrm{rxn}}=-1790 \mathrm{~kJ}
\end{array}\)
If a bottle of nail polish remover contains 155 g of acetone, how much heat is released by its complete combustion?
ANSWER:Step 1 of 2
The given Chemical reaction is
\(\begin{array}{l}
\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(\mathrm{l})+4 \mathrm{O}_{2} \rightarrow 3 \mathrm{CO}_{2}(\mathrm{~g})+3 \mathrm{H}_{2} \mathrm{O} \\
\Delta \mathrm{H}_{\mathrm{rxn}}=-1790 \mathrm{~kJ}
\end{array}\)
We have to determine the amount of heat emitted by acetone complete combustion.
We are given that
\(\begin{array}{l}
\mathrm{m}\left(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\right)=155 \mathrm{~g} \\
\mathrm{M}\left(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\right)=58 \frac{\mathrm{g}}{\mathrm{mol}}
\end{array}\)
Reviews
Review this written solution for 13762) viewed: 2664 isbn: 9780321910295 | Introductory Chemistry - 5 Edition - Chapter 8 - Problem 73p
Thank you for your recent purchase on StudySoup. We invite you to provide a review below, and help us create a better product.
No thanks, I don't want to help other students