Solution Found!
Octane (C8H18) is a component of gasoline that burns according to the equation: What
Chapter 8, Problem 75P(choose chapter or problem)
Octane (\(\mathrm{C}_{8} \mathrm{H}_{18}\)) is a component of gasoline that burns according to the equation:
\(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l)+4 \mathrm{O}_{2}(g) \rightarrow 3 \mathrm{CO}_{2}(g)+3 \mathrm{H}_{2} \mathrm{O}(g)\)
\(\Delta H_{r x n}=-1790 k J\)
What mass of octane (in g) is required to produce \(1.55 \times 10^{3} \mathrm{~kJ}\) of heat?
Equation Transcription:
C8H18
1.55 103 kJ
Text Transcription:
C_8H_18
C_3H_6O(l)+4O_2(g) rightarrow 3CO_2(g)+3H_2O(g)
Delta H_rxn=-1790kJ
1.55 times 10^3 kJ
Questions & Answers
QUESTION:
Octane (\(\mathrm{C}_{8} \mathrm{H}_{18}\)) is a component of gasoline that burns according to the equation:
\(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l)+4 \mathrm{O}_{2}(g) \rightarrow 3 \mathrm{CO}_{2}(g)+3 \mathrm{H}_{2} \mathrm{O}(g)\)
\(\Delta H_{r x n}=-1790 k J\)
What mass of octane (in g) is required to produce \(1.55 \times 10^{3} \mathrm{~kJ}\) of heat?
Equation Transcription:
C8H18
1.55 103 kJ
Text Transcription:
C_8H_18
C_3H_6O(l)+4O_2(g) rightarrow 3CO_2(g)+3H_2O(g)
Delta H_rxn=-1790kJ
1.55 times 10^3 kJ
ANSWER:
Step 1 of 2
The given Chemical reaction is
We have to determine the amount of .
We are given that