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# A solution contains an unknown mass of dissolved barium ## Problem 79P Chapter 8

Introductory Chemistry | 5th Edition

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Problem 79P

PROBLEM 79P

A solution contains an unknown mass of dissolved barium ions. When sodium sulfate is added to the solution, a white precipitate forms. The precipitate is filtered and dried and found to have a mass of 258 mg. What mass of barium was in the original solution? (Assume that all of the barium was precipitated out of solution by the reaction.)

Step-by-Step Solution:

Solution 79P

Step 1:

Amount of precipitate formed = 258 mg

The chemical equation for the reaction happening here is :

Ba2+ (aq) + Na2SO4 (aq)  → BaSO4 (s) + 2Na+

Let’s find out the number of moles of BaSO4 formed :

Number of moles (n) = Molar mass of BaSO4 = 233.38 g/mol.

Barium precipitate formed is in mg, let’s convert to g :

1 g = 1000 mg

Therefore, 0.258mg in gram is :

258 mg  = 0.258g

Now, let’s find the number of moles :

n = n = 0.0011 moles

Therefore, the number of moles of Ba2+ in the original solution is 0.0011 moles.

Step 2 of 2

##### ISBN: 9780321910295

The full step-by-step solution to problem: 79P from chapter: 8 was answered by Patricia, our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 79P from 8 chapter was answered, more than 267 students have viewed the full step-by-step answer. This full solution covers the following key subjects: solution, mass, barium, precipitate, added. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by Patricia and is associated to the ISBN: 9780321910295. The answer to “A solution contains an unknown mass of dissolved barium ions. When sodium sulfate is added to the solution, a white precipitate forms. The precipitate is filtered and dried and found to have a mass of 258 mg. What mass of barium was in the original solution? (Assume that all of the barium was precipitated out of solution by the reaction.)” is broken down into a number of easy to follow steps, and 60 words.

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