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# Consider the reaction:2 N2(g) + 5 O2(g) + 2 H2O(g) ? 4

ISBN: 9780321910295 34

## Solution for problem 77P Chapter 8

Introductory Chemistry | 5th Edition

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Problem 77P

PROBLEM 77P

Consider the reaction:

2 N2(g) + 5 O2(g) + 2 H2O(g) → 4 HNO3(g)

If a reaction mixture contains 28 g of N2, 150 g of O2, and 36 g of H2O, what is the limiting reactant? (Try to do this problem in your head without any written calculations.)

Step-by-Step Solution:
Step 1 of 3

Solution 77P

The reaction requires certain amounts of each reactant to occur.

For each reaction, you need 2 "parts" N2, 5 parts O2, 2 parts H20.

We need 2 parts N2 and 2 parts H20, but there's only 28g of N2. So between just N2 and H2O, N2 is the limiting reactant.

Let's look at the O2 now. It's a bit more complicated since it's not comparing 2 parts to 2 parts, but instead 2 parts to 5 parts.

To get the 28 grams and 150 grams to "align", let's multiply the 28 grams by the ratio 5:2, since there are 5 parts O2 and 2 parts N2.

28 * (5 / 2) = 70.

Since 70 < 150,...

Step 2 of 3

Step 3 of 3

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