Hydrogen gas can be prepared in the laboratory by a single-displacement reaction in which solid zinc reacts with hydrochloric acid. How much zinc in grams is required to make 14.5 g of hydrogen gas through this reaction?
Step 1 of 3
Here, we are going to calculate the mass of Zinc to make hydrogen gas through the reaction.
Zn(s) + 2HCl(g) ------> ZnCl2(s) +H2(g)
Molar mass of Zn =65.39 g/mol
Molar mass of H2 =2 x1.008 g/mol = 2.016 g/mol
Thus,the conversion factors
g Zn(s)= mol Zn(s) = g H2(g) = mol H2(g)
Thus the amount of Zinc required to produce 14.5 g hydrogen gas is
= 14.5 g of H2(g) x x x
= = 470.31 g Zn(s)
Therefore, 470.31 g Zn(s) is required to produce 14.5 g of hydrogen gas through that reaction.
Textbook: Introductory Chemistry
Author: Nivaldo J Tro
The answer to “Hydrogen gas can be prepared in the laboratory by a single-displacement reaction in which solid zinc reacts with hydrochloric acid. How much zinc in grams is required to make 14.5 g of hydrogen gas through this reaction?” is broken down into a number of easy to follow steps, and 37 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 87P from chapter: 8 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 87P from 8 chapter was answered, more than 1108 students have viewed the full step-by-step answer. This full solution covers the following key subjects: zinc, reaction, gas, hydrogen, much. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.