Sodium peroxide (Na2O2) reacts with water to form sodium

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Problem 88P Chapter 8

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Introductory Chemistry | 5th Edition

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Problem 88P

PROBLEM 88P

Sodium peroxide (Na2O2) reacts with water to form sodium hydroxide and oxygen, gas. Write a balanced equation for the reaction and determine how much oxygen in grams is formed by the complete reaction of 35.23 g of Na2O2.

Step-by-Step Solution:

Solution 88P

Here, we are going to write a balanced equation for the given reaction and calculate the mass of oxygen formed by the complete reaction.

Step 1:

Sodium peroxide reacts with water to form sodium hydroxide and oxygen gas. The balanced molecular equation for the given reaction is:

                        2Na2O2(aq) + 2H2O(l) → 4NaOH(aq) + O2(g)

Step 2:

Given mass of Na2O2 = 35.23 g

Molar mass of Na2O2 = 77.98 g/mol

Therefore, number of moles of Na2O2 = given mass/molar mass

                                        =

                                        = 0.45 mol

Step 3 of 3

Chapter 8, Problem 88P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo Tro
ISBN: 9780321910295

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