Sodium peroxide (Na2O2) reacts with water to form sodium hydroxide and oxygen, gas. Write a balanced equation for the reaction and determine how much oxygen in grams is formed by the complete reaction of 35.23 g of Na2O2.
Here, we are going to write a balanced equation for the given reaction and calculate the mass of oxygen formed by the complete reaction.
Sodium peroxide reacts with water to form sodium hydroxide and oxygen gas. The balanced molecular equation for the given reaction is:
2Na2O2(aq) + 2H2O(l) → 4NaOH(aq) + O2(g)
Given mass of Na2O2 = 35.23 g
Molar mass of Na2O2 = 77.98 g/mol
Therefore, number of moles of Na2O2 = given mass/molar mass
= 0.45 mol