PROBLEM 90P
Pure oxygen gas can be prepared in the laboratory by the decomposition of solid potassium chlorate to form solid potassium chloride and oxygen gas. How much oxygen gas in grams can be prepared from 45.8 g of potassium chlorate?
Solution 90P
Here, we are going to calculate the mass of oxygen gas prepared from 45.8 g of potassium chlorate.
Step 1:
The balanced molecular equation for the decomposition of solid potassium chlorate to form solid potassium chloride and oxygen gas is given below:
2KClO3(s) → 2KCl(s) + 3O2(g)