Two of the emission wavelengths in the hydrogen emission

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

ISBN: 9780321910295 34

Solution for problem 42P Chapter 9

Introductory Chemistry | 5th Edition

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Problem 42P

PROBLEM 42P

Two of the emission wavelengths in the hydrogen emission spectrum are 656 nm and 486 nm. One of these is due to the n = 4 to n = 2 transition, and the other is due to the n = 3 to n = 2 transition. Which wavelength corresponds to which transition?

Step-by-Step Solution:

Solution 42P

Here, we are going to identify which of the given wavelengths corresponds to the given transitions.

Step 1:

It is already known that, when an electron jumps from a lower orbit to a higher orbit, it absorbs energy whereas when the electron jumps from higher orbit to lower orbit, it emits energy.

Thus, n = 4 to n = 2 transition corresponds to higher emission of energy compared to n = 3 to n = 2 transition.

Step 2 of 2

Chapter 9, Problem 42P is Solved

Textbook: Introductory Chemistry

Edition: 5

Author: Nivaldo J Tro

ISBN: 9780321910295

This full solution covers the following key subjects: transition, due, emission, spectrum, other. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The full step-by-step solution to problem: 42P from chapter: 9 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “Two of the emission wavelengths in the hydrogen emission spectrum are 656 nm and 486 nm. One of these is due to the n = 4 to n = 2 transition, and the other is due to the n = 3 to n = 2 transition. Which wavelength corresponds to which transition?” is broken down into a number of easy to follow steps, and 52 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Since the solution to 42P from 9 chapter was answered, more than 335 students have viewed the full step-by-step answer. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.