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Use the periodic table to identify the element with each electron configuration.(a)

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 75P Chapter 9

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 75P

Use the periodic table to identify the element with each electron configuration.

(a) \([N e] 3 s^{2} 3 p^{5}\)

(b) \([A r] 4 s^{2} 3 d^{10} 4 p^{1}\)

(c) \([A r] 4 s^{2} 3 d^{6}\)

(d) \([K r] 5 s^{1}\)

Equation Transcription:

Text Transcription:

[Ne]3s^2 3p^5

[Ar]4s^2 3d^10 4p^1

[Ar]4s^2 3d^6

[Kr]5s^1

Step-by-Step Solution:
Step 1 of 3

Solution 75P

Here, we have to identify the element with each configuration.

(a) [Ne]3s23p5

The atomic number of the element is 17

From electronic configuration, valence electron of the element = 7

Thus, it is an element of Group 17 (VIIA).

Therefore, the name of the element is Chlorine (Cl).

(b) [Ar]4s23d104p1

The atomic number of the element is 31

From electronic configuration, valence electron of the element = 3

Thus, it is an element of Group 13 (IIIA).

Therefore, the name of the element is Gallium (Ga).

(c) [Ar]4s23d6

The atomic number of the element is 26

From electronic configuration, valence electron of the element = 8

Thus, it is an element of Group 8 (8B).

Therefore, the name of the element is Iron (Fe).

(d) [Kr]5s1

The atomic number of the element is 37

From electronic configuration, valence electron of the element = 1

Thus, it is an element of Group I (IA).

Therefore, the name of the element is Rubidium  (Rb).

Step 2 of 3

Chapter 9, Problem 75P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Use the periodic table to identify the element with each electron configuration.(a)