PROBLEM 103P

When an electron makes a transition from the n = 3 to the n = 2 hydrogen atom Bohr orbit, the energy difference between these two orbits (3.0 × 1019 J) is emitted as a photon of light. The relationship between the energy of a photon and its wavelength is given by E = hc/λ, where E is the energy of the photon in J, h is Planck's constant (6.626 × 10−34 J.s), and c is the speed of light (3.00 × 108 m/s). Find the wavelength of light emitted by hvdroeen atoms when an electron makes this transition.

Solution 103P

Given :

Electron makes a transition from the n = 3 to the n = 2 hydrogen atom Bohr orbit.

The energy difference between these two orbits emitted as a photon of light= (3.0 × 1019 J).

The relationship between the energy of a photon and its wavelength is given by :

E = ,

where, E = energy of the photon in J,

h = Planck's constant = 6.626 × 10−34 J.s

c = Speed of light = 3.00 × 108 m/s.

Wavelength of light emitted by hydrogen atoms when an electron makes this transition = ?

Here, we are given the energy , we have to calculate wavelength ()

=...