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Excessive exposure to sunlight increases the risk of skin

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 113P Chapter 9

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 113P

PROBLEM 113P

Excessive exposure to sunlight increases the risk of skin cancer because some of the photons have enough energy to break chemical bonds in biological molecules. These bonds require approximately 250-800 kj/mol of en­ergy to break. The energy of a single photon is given by E = hc/ λ, where E is the energy of the photon in J, h is Planck's constant (6.626 × 10~34 J • s), and c is the speed of light (3.00 × 108 m/s). Determine which kinds of light contain enough energy to break chemical bonds in bio­logical molecules by calculating the total energy in 1 mol of photons for light of each wavelength.

(a) infrared light (1500 nm)

(b) visible light (500 nm)

(c) ultraviolet light (150 nm)

Step-by-Step Solution:

Solution 113P

Here, we are going to calculate the total energy in 1 mol of photons for light of each wavelength.

Step 1:

The energy of a single photon = hc/ƛ

Therefore, energy of 1 mol of photons = NA hc/ƛ

Given, wavelength(ƛ) = 1500 nm(infrared light) = 1500 x 10-9 m = 1.5 x 10-6 m   [1 nm = 10-9 m]

                h = 6.626 x 10-34 J.s

                C = 3 x 108 m/s

                NA = 6.02 x 1023

Therefore, energy of 1 mol of photons = [(6.02 x 1023)(6.626 x 10-34 J.s)(3 x 108 m/s)] / (1.5 x 10-6 m)

                                          = 79.78 x 103 J

                                          = 79.8 kJ

b)        Given, wavelength(ƛ) = 500 nm(visible light) = 500 x 10-9 m = 5 x 10-7 m   [1 nm = 10-9 m]

                h = 6.626 x 10-34 J.s

                C = 3 x 108 m/s

                NA = 6.02 x 1023

Therefore, energy of 1 mol of photons = [(6.02 x 1023)(6.626 x 10-34 J.s)(3 x 108 m/s)] / (5 x 10-7 m)

                                          = 23.93 x 104 J

                                          = 239.3 kJ

c)        Given, wavelength(ƛ) = 150 nm(ultraviolet light) = 150 x 10-9 m = 1.50 x 10-7 m   [1 nm = 10-9 m]

                h = 6.626 x 10-34 J.s

                C = 3 x 108 m/s

                NA = 6.02 x 1023

Therefore, energy of 1 mol of photons = [(6.02 x 1023)(6.626 x 10-34 J.s)(3 x 108 m/s)] / (1.50 x 10-7 m)

                                          = 79.78 x 104 J

                                          = 797.8 kJ

Step 2 of 2

Chapter 9, Problem 113P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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