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You learned in this chapter that ionization generally

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 111P Chapter 9

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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1
Problem 111P

PROBLEM 111P

You learned in this chapter that ionization generally increases as you move from left to right across the periodic table. However, consider the data below, which shows the ionization energies of the period 2 and 3 elements:

Group

Period 2 Elements

Ionization Energy (kJ/mol)

Period 3 Elements

Ionization Energy (kJ/mol)

1A

Li

520

Na

496

2A

Be

899

Mg

738

3A

B

801

Al

578

4A

C

1086

Si

786

5A

N

1402

P

1012

6A

O

1314

S

1000

7A

F

1681

Cl

1251

8A

Ne

2081

Ar

1521

Notice that the increase is not uniform. In fact, ionization energy actually decreases a bit in going from elements in group 2A to 3A and then again from 5A to 6A. Use what you know about electron configurations to explain why these dips in ionization energy exist.

Step-by-Step Solution:
Step 1 of 3

Solution 110P

Here, we have to calculate  the energy of 1 mol of photons with a wavelength of 632 nm.

We know that

A photon of wavelength λ has an energy (E) given by the equation:

E = hc/λ, -----(1)

where E is the energy of the photon in J, h is Planck's constant  and c is the speed of light.

Given that,

Planck's constant h = 6.626 × 10−34 J• s

Speed of Light c = (3.00 × 108 m/s)

Wavelength of light =...

Step 2 of 3

Chapter 9, Problem 111P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

The full step-by-step solution to problem: 111P from chapter: 9 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 111P from 9 chapter was answered, more than 278 students have viewed the full step-by-step answer. The answer to “You learned in this chapter that ionization generally increases as you move from left to right across the periodic table. However, consider the data below, which shows the ionization energies of the period 2 and 3 elements:GroupPeriod 2 ElementsIonization Energy (kJ/mol)Period 3 ElementsIonization Energy (kJ/mol)1ALi520Na4962ABe899Mg7383AB801Al5784AC1086Si7865AN1402P10126AO1314S10007AF1681Cl12518ANe2081Ar1521Notice that the increase is not uniform. In fact, ionization energy actually decreases a bit in going from elements in group 2A to 3A and then again from 5A to 6A. Use what you know about electron configurations to explain why these dips in ionization energy exist.” is broken down into a number of easy to follow steps, and 91 words. This full solution covers the following key subjects: ionization, elements, Energy, period, Group. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.

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