Give the bond angles for each of the geometries in the

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

ISBN: 9780321910295 34

Solution for problem 15Q Chapter 10

Introductory Chemistry | 5th Edition

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Problem 15Q

PROBLEM 15Q

Give the bond angles for each of the geometries in the preceding question.

Step-by-Step Solution:

Step 1 of 3

Solution 15Q

Here, we are going to determine the bond angles for each geometry.

The molecular geometry of a molecule depends on (i) number of electron group around the central atom (ii) Number of bonding groups and lone pairs.

(a) two electron groups

Both the electron group is bonding pair electron.

The geometry of the molecule having two electron groups is Linear.

For example: BeH2, HCN and CO2

Therefore, the bond angle for Linear geometry is 180o.

(b) three electron groups

Three electron groups are bonding pair of electrons.

The geometry of the...

Step 2 of 3

Chapter 10, Problem 15Q is Solved

Step 3 of 3

Textbook: Introductory Chemistry

Edition: 5

Author: Nivaldo J Tro

ISBN: 9780321910295

This full solution covers the following key subjects: Angles, Bond, Geometries, give, preceding. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The answer to “Give the bond angles for each of the geometries in the preceding question.” is broken down into a number of easy to follow steps, and 13 words. Since the solution to 15Q from 10 chapter was answered, more than 323 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 15Q from chapter: 10 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.