Write the Lewis structure for each molecule.(a) PH3(b)

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Problem 47P Chapter 10

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Introductory Chemistry | 5th Edition

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Problem 47P

PROBLEM 47P

Write the Lewis structure for each molecule.

(a) PH3

(b) SCl2

(c) F2

(d) HI

Step-by-Step Solution:

Solution 47P

Step 1:

(a)PH3

In PH3 the central atom is P, surrounded by three H atoms.

15P [Ne] 3s2 3p3    1H 1s1

Total number of valence electrons = 5 + 1(3) =8

Lewis structure of PH3

Step 2:

(b)SCl2

In SCl2, the central atom is S, surrounded by Cl atom.

16S [Ne] 3s2 3p4    17Cl [Ne] 3s2 3p5

Total number of valence electrons = 6 + 7 (2)= 20

Lewis structure of SCl2 

           

Step 3 of 4

Chapter 10, Problem 47P is Solved
Step 4 of 4

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo Tro
ISBN: 9780321910295

Introductory Chemistry was written by Patricia and is associated to the ISBN: 9780321910295. This full solution covers the following key subjects: lewis, molecule, scl, structure, Write. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The full step-by-step solution to problem: 47P from chapter: 10 was answered by Patricia, our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 47P from 10 chapter was answered, more than 1571 students have viewed the full step-by-step answer. The answer to “Write the Lewis structure for each molecule.(a) PH3(b) SCl2(c) F2(d) HI” is broken down into a number of easy to follow steps, and 11 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.

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