Write the Lewis structure for each molecule.(a) C2H2(b)

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Problem 51P Chapter 10

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Introductory Chemistry | 5th Edition

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Problem 51P

PROBLEM 51P

Write the Lewis structure for each molecule.

(a) C2H2

(b) C2H4

(c) N2H2

(d) N2H4

Step-by-Step Solution:

Solution 51P

Here, we are going to write the Lewis structure for each molecule.

Lewis structure of an element is the representation of the chemical symbol surrounded by dots which represent the valence electrons.

Rules for construct a Lewis structure.

Calculation of  valence electrons are in the molecule that needs to be shown on the Lewis Structure. For a molecule having  charge,  add an electron for every negative charge and remove an electron for every positive charge.The single bonds are drawn in  initial framework, called the skeleton, of the molecule. The non-central atoms i.e. the terminal atoms should be fulfilled octet by using the lone-pairs of electrons.Distribute the electrons among atoms to fulfill the octet or duet for Hydrogen atom.If there are extra lone-pair electrons and the octet rule is not filled for the central atom, use the extra electrons to form double or triple bonds around the central atom.the formal charge of each atom should be known.

(a) C2H2

Step 1:  Calculation of total number of valence electrons for the molecule to draw Lewis structure.

Valence electron of C = 4

Valence electron of H =1

Total number of valence electrons in C2H2 molecule = 2 x 4 + 2 = 10 e

Step 2: Distribution of electrons around the atoms to fulfil the octet or duet.

Step 3:  Each atom should fulfil the octet.

 Here, each C atom satisfy the octet and each H atom satisfy the duet.

Therefore, the Lewis structure for C2H2 molecule is

(b) C2H4

Step 1:  Calculation of total number of valence electrons for the molecule to draw Lewis structure.

Valence electron of C = 4

Valence electron of H =1

Total number of valence electrons in C2H2 molecule = 2 x 4 + 4 = 12 e

Step 2: Distribution of electrons around the atoms to fulfil the octet or duet.

Step 3:  Each atom should fulfil the octet.

Here, each C atom satisfy the octet and each H atom satisfy the duet.

Therefore, the Lewis structure for C2H4 molecule is

(c) N2H2

Step 1:  Calculation of total number of valence electrons for the molecule to draw Lewis structure.

Valence electron of N = 5

Valence electron of H =1

Total number of valence electrons in C2H2 molecule = 2 x 5 + 2 = 12 e

Step 2: Distribution of electrons around the atoms to fulfil the octet or duet.

Step 3:  Each atom should fulfil the octet.

Here, each C atom satisfy the octet and each H atom satisfy the duet.

Therefore, the Lewis structure for N2H2 molecule is

(d) N2H4

Step 1:  Calculation of total number of valence electrons for the molecule to draw Lewis structure.

Valence electron of N = 5

Valence electron of H =1

Total number of valence electrons in C2H2 molecule = 2 x 5 +4 = 14 e

Step 2: Distribution of electrons around the atoms to fulfil the octet or duet.

Step 3 of 3

Chapter 10, Problem 51P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo Tro
ISBN: 9780321910295

The answer to “Write the Lewis structure for each molecule.(a) C2H2(b) C2H4(c) N2H2(d) N2H4” is broken down into a number of easy to follow steps, and 11 words. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The full step-by-step solution to problem: 51P from chapter: 10 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: lewis, molecule, structure, Write. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. Since the solution to 51P from 10 chapter was answered, more than 257 students have viewed the full step-by-step answer.

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