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Determine whether each compound is ionic or covalent and write the appropriate Lewis

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 96P Chapter 10

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 96P

PROBLEM 96P

Determine whether each compound is ionic or covalent and write the appropriate Lewis structure.

(a) HCN

(b) CIF

(c) MgI2

(d) CaS

Step-by-Step Solution:
Step 1 of 3

Solution 96P

In chemical bonds, atoms can either transfer or share their valence electrons. In the extreme case where one or more atoms lose electrons and other atoms gain them in order to produce a noble gas electron configuration, the bond is called an ionic bond.

Typical of ionic bonds are those in the alkali halides such as sodium chloride, NaCl.

Covalent chemical bonds involve the sharing of a pair of valence electrons by two atoms, in contrast to the transfer of electrons in ionic bonds. Such bonds lead to stable molecules if they share electrons in such a way as l 

Noble gas configuration for each atom.

Hydrogen gas forms the simplest covalent bond in the diatomic hydrogen molecule. The halogens such as chlorine also exist as diatomic gases by forming covalent bonds. The nitrogen and oxygen which makes up the bulk of the atmosphere also exhibits covalent bonding in forming diatomic molecules.

(a) HCN

For the HCN Lewis structure, calculate the total number of valence electrons for the HCN molecule. After determining how many valence electrons there are in HCN, place them around the central atom to complete the octets. ... Note: Hydrogen (H) atoms always go on the outside of a Lewis structure.

Image result for lewis structure hcn

(b) CIF

For the ClF Lewis structure, calculate the total number of valence electrons for the ClF molecule. After determining how many valence electrons there are in ClF, place them around the central atom to complete the octets.

Image result for lewis structure cif

(c) MgI2

Iodine needs 7 electrons and Magnesium needs 2 (because of their group number in the periodic table) and there are 2 Iodines so the total amount is 14. You get 8 from the two double bonds and then fill in Iodine's octet until you reach 14. Iodine does not have to have a full octet because it's below the 3rd period and those elements often bend the octet rules.

:I = Mg = I:

(d) CaS

Ca has two electrons around it and S has 6 electrons around it. S is very electronegative so it will take both electrons from Ca.

Thus, the lewis dot structure will be S with 6 electrons around it, single bonded to Ca. From this, we can assume that Ca donates both electrons to bond with S. This makes sense since S has achieved octet.

Image result for lewis structure cas

Step 2 of 3

Chapter 10, Problem 96P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The answer to “Determine whether each compound is ionic or covalent and write the appropriate Lewis structure.(a) HCN(b) CIF(c) MgI2(d) CaS” is broken down into a number of easy to follow steps, and 18 words. The full step-by-step solution to problem: 96P from chapter: 10 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This full solution covers the following key subjects: appropriate, CAS, cif, compound, covalent. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Since the solution to 96P from 10 chapter was answered, more than 509 students have viewed the full step-by-step answer.

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Determine whether each compound is ionic or covalent and write the appropriate Lewis