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Consider the redox reaction.Ca(s) + Br2(g)?CaBr2(s)Draw the Lewis structure for each

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 104P Chapter 10

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 104P

PROBLEM 104P

Consider the redox reaction.

Ca(s) + Br2(g)→CaBr2(s)

Draw the Lewis structure for each reactant and product and determine which reactant was oxidized and which one was reduced.

Step-by-Step Solution:
Step 1 of 3

Solution 104P

Here, we are going to write Lewis structure of reactant and product as well as find out the oxidized and reduced form of the reactant.

Oxidation reaction is defined as the increase in oxidation state and reduction is the decrease in oxidation state.

Lewis structures of reactants

Ca: Valence electron of Ca =2

The Lewis structure of Ca is as follows.

Br2:

Valence electron of Br = 7

Total electrons in Br2 = 7+ 7 =14 e

The Lewis structure of Br2 is

Lewis structure of CaBr2(s):

Valence electron of Br = 7

Valence electron of Ca =2

Total valence electron of CaBr2 = 2+7 x2 =16 e

Thus, the lewis structure of CaBr2 is as follows.

The oxidation-reduction reaction is as follows.

Here, Ca(s) increases its oxidation state 0 to 2+ , so it is oxidized and Br2 decreases its oxidation state 0 to -1. Therefore, Br2 is reduced.

Thus, Ca(s) is oxidized and Br2(g) is reduced in the above reaction.

Step 2 of 3

Chapter 10, Problem 104P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Consider the redox reaction.Ca(s) + Br2(g)?CaBr2(s)Draw the Lewis structure for each