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Each molecule listed contains an expanded octet (10 or 12

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Problem 107P Chapter 10

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Introductory Chemistry | 5th Edition

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Problem 107P

PROBLEM 107P

Each molecule listed contains an expanded octet (10 or 12 electrons) around the central atom. Write the Lewis structure for each molecule.

(a) PF5

(b) SF4

(c) SeF4

Step-by-Step Solution:

Solution 107P

Here, we are going to write the lewis structure for the given molecules.

Step 1:

The Lewis dot structure provide a picture of bonding in molecules and ions in terms of the shared pairs of electrons and the octet rule. While such a picture may not explain the bonding and behaviour of a molecule completely, it does help in understanding the formation and properties of a molecule to a large extent. Writing of Lewis dot structures of molecules is, therefore, very useful.

Step 2:

There are certain rules to draw the Lewis structure. They are:

The total number of electrons required for writing the structures are obtained by adding the valence electrons of the combining atoms. For anions, each negative charge would mean addition of one electron. For cations each positive charge would result in subtraction of one electron from the total number of valence electrons.Knowing the chemical symbols of the combining atoms and having knowledge of the skeletal structure of the compound, it is easy to distribute the total number of electrons as bonding shared pairs between the atoms in proportion to the total bonds.In general, the least electronegative atom occupies the central position in the molecule/ion.After accounting for the shared pairs of electrons for single bonds, the remaining electron pairs are either utilized for multiple bonding or remain as the lone pairs. The basic requirement being that each bonded atom gets an octet of electrons.

But, in a number of compounds of elements in and beyond the third period of the periodic table, there are more than eight valence electrons around central atom. This is termed as the expanded octet. The octet rule does not apply in such cases.

Step 3:

PF5

Number of valence electrons in P = 5

Number of valence electrons in F = 7

Total number of valence electrons in PF5 = 5 + (7 x 5) = 40

Here, phosphorus(P) shares its 5 valence electrons with the five fluorine atoms and as a result expands its octet to 10 electrons. The lewis structure for the molecule is:

                        

Step 4 of 5

Chapter 10, Problem 107P is Solved
Step 5 of 5

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo Tro
ISBN: 9780321910295

Introductory Chemistry was written by Patricia and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Since the solution to 107P from 10 chapter was answered, more than 236 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 107P from chapter: 10 was answered by Patricia, our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: molecule, lewis, central, contains, electrons. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The answer to “Each molecule listed contains an expanded octet (10 or 12 electrons) around the central atom. Write the Lewis structure for each molecule.(a) PF5(b) SF4(c) SeF4” is broken down into a number of easy to follow steps, and 25 words.

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