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Solved: PROBLEM 23P Convert each measurement to atm. (a)

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 23P Chapter 11

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 23P

PROBLEM 23P Convert each measurement to atm. (a)? 1277 mm Hg (b)? 2.38 × 105 Pa (c)? 127 psi (d)? 455 torr

Step-by-Step Solution:

Solution 23P Step 1: (a) 1277 mm Hg Pressure of gas = 1277 mm Hg It is known that 1 atm = 760 mm Hg Conversion factor used = 1 atm/ 760 mm Hg We have multiply the given pressure of the gas in mmHg with the conversion factor, to calculate the pressure in the atmosphere. Hence, 1277 mm Hg× 1 atm = 1.680 atm 760mm Hg Therefore the pressure of the gas in atmosphere is 1.680atm Step 2: (b) 2.38 × 10 Pa Pressure of gas = 2.38 × 10 Pa 5 We will use the conversion factor, to convert the pressure in pa to atm. pressure in atm = (pressure on Pa) × (1 atm/1.01325 x 10 Pa) 5 = (2.38 × 10 Pa) ×(1 atm/1.01325 ×10 Pa) 5 =2.38 × 10 /1.01325 × 1 0 atm ((the Pa unit cancels out) =2.3488 atm Therefore the pressure of the gas in atmosphere is 2.3488 atm

Step 3 of 4

Chapter 11, Problem 23P is Solved
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Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: PROBLEM 23P Convert each measurement to atm. (a)

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