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Solved: PROBLEM 23P Convert each measurement to atm. (a)

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 23P Chapter 11

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 23P

Convert each measurement to atm.

(a) \(1277 \mathrm{~mm}\ \mathrm{Hg}\)

(b) \(2.38 \times 10^{5} \mathrm{~Pa}\)

(c) \(127 \text { psi }\)

(d) \(455 \text { torr }\)

Equation Transcription:

Text Transcription:

1277 mm Hg

2.38 times 10^5 Pa

127 psi

455 torr

Step-by-Step Solution:

Solution 23P Step 1: (a) 1277 mm Hg Pressure of gas = 1277 mm Hg It is known that 1 atm = 760 mm Hg Conversion factor used = 1 atm/ 760 mm Hg We have multiply the given pressure of the gas in mmHg with the conversion factor, to calculate the pressure in the atmosphere. Hence, 1277 mm Hg× 1 atm = 1.680 atm 760mm Hg Therefore the pressure of the gas in atmosphere is 1.680atm

Step 2 of 4

Chapter 11, Problem 23P is Solved
Step 3 of 4

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: PROBLEM 23P Convert each measurement to atm. (a)