PROBLEM 24P Convert each measurement to atm. (a)? 921 torr (b)? 4.8 × 104Pa (c)? 87.5 psi (d)? 34.22 in. Hg

Solution 24P Step 1: (a)921 torr The pressure of gas = 921 torr It is known that 760 torr = 1 atm 921 torr = 921 torr ×1 atm/760 torr = 1.21184 Therefore the pressure of the gas in atmosphere is 1.21184 atm. Step 2: (b) 4 .8× 10 Pa Pressure of gas = 4.8× 10 Pa 4 We will use the conversion factor, to convert the pressure in pa to atm. pressure in atm = (pressure on Pa) × (1 atm/1.01325 x 10 Pa) 5 4 5 = (4.8× 10 Pa) ×(1 atm/1.01325 ×10 Pa) =4.8× 10 Pa /1.01325 × 10 atm ((the Pa unit cancels out) =4.7372× 10 atm -1 -1 Therefore the pressure of the gas in atmosphere is 4.7372× 10 atm