Using the integral of see3 u By reduction formula 4 in

Chapter 4, Problem 64E

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QUESTION:

Using the integral of \(\sec ^{3} u\) By reduction formula 4 in Section 7.2,

\(\int \sec ^{3} u d u=\frac{1}{2}(\sec u \tan u+\ln |\sec u+\tan u|)+C\).

Graph the following functions and find the area under the curve on the given interval.

\(f(x)=\left(4+x^{2}\right)^{1 / 2}\),[0,2]

Questions & Answers

QUESTION:

Using the integral of \(\sec ^{3} u\) By reduction formula 4 in Section 7.2,

\(\int \sec ^{3} u d u=\frac{1}{2}(\sec u \tan u+\ln |\sec u+\tan u|)+C\).

Graph the following functions and find the area under the curve on the given interval.

\(f(x)=\left(4+x^{2}\right)^{1 / 2}\),[0,2]

ANSWER:

Problem 64ESolution:-Step1Given thatf(x)=, [0,2]Step2 To findGraph the following functions and find the area under

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