A gas sample with a volume of 5.3 L has a pressure of 735 mm Hg at 28 °C. What is the pressure of the sample if the volume remains at 5.3 L but the temperature rises to 86 °C?
Volume (V1)=5.3 L.
Pressure (P1)=735 mm Hg .
Temperature (T1)=28 oC.
Volume (V2)= ?
We know that
To solve this, use Gay-Lussac's law:
P₁/T₁ = P₂/T₂ ==> P₂ = P₁T₁/T₂.
Plugging in the given information yields:
P₂ = P₁T₁/T₂
= [(75 mmHg)(359 K)]/(301 K)
= 89 mmHg.