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Force on a moving charge Answer the following questions
Chapter 10, Problem 40E(choose chapter or problem)
37-40. Force on a moving charge Answer the following questions about force on a moving charge.
A proton \(\left(q=1.6 \times 10^{-19} \mathrm{C}\right)\) with velocity \(2 \times 10^{6} \mathbf{j} \ \mathrm{m} / \mathrm{s}\) experiences a force \(\mathbf{F}=5 \times 10^{-12} \mathbf{k}\) (N) as it passes through the origin. Find the magnitude and direction of the magnetic field at that instant.
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QUESTION:
37-40. Force on a moving charge Answer the following questions about force on a moving charge.
A proton \(\left(q=1.6 \times 10^{-19} \mathrm{C}\right)\) with velocity \(2 \times 10^{6} \mathbf{j} \ \mathrm{m} / \mathrm{s}\) experiences a force \(\mathbf{F}=5 \times 10^{-12} \mathbf{k}\) (N) as it passes through the origin. Find the magnitude and direction of the magnetic field at that instant.
ANSWER:Solution 40EStep 1 of 2:In this problem we need to find the magnitude and direction of the magnetic field (B) at that instant.Given that a proton ( q = 1.6 with velocity v = 2 experiences a force in newtons of F = 5 as it passes through the origin.We know that F = q ( v |F| = |q| |v |F| = |q| |v| |B| sin( , where is the angle .Since , F||k , and v||jit follows that their cross product B is parallel to ‘i’.So , B = t i , for some t .Therefore , |F| = |q| |v| |B| sin( |F| = |q |v||B| sin( , since |F| = |q| |v| |B| , since sin( = 1