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A sample of gas has a mass of 0.555 g. Its volume is 117 mL at a temperature of 85 °C

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 72P Chapter 11

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 72P

PROBLEM 72P

A sample of gas has a mass of 0.555 g. Its volume is 117 mL at a temperature of 85 °C and a pressure of 753 mm Hg. Find the molar mass of the gas.

Step-by-Step Solution:
Step 1 of 3

Solution 72P

Given that

Mass =0.555g

Volume =117 mL.

Temperature= 85oC.

Pressure =753 mmHg. 

We know that

With the ideal gas equation PV=nRT

Explanation:

Boyle's law, published in 1662, established a relationship between gas pressure and volume. Say you have a gas in a cylinder, and then you make the volume twice as big by pulling on a piston. The pressure is reduced by half. This is called an inverse relationship.

Charles law, discovered in 1801, determined that if you keep the pressure constant, the volume of a gas is directly proportional to its temperature. However, you must use the Kelvin temperature scale that starts at absolute zero, -273.15 degrees Celsius.

Avogadro's law states that there an equal number of gas atoms or molecules in a given volume of gas. And he invented the concept of the mole, which is defined as the number of atoms in 12 grams of Carbon 12. This is 6.02x1023. What they determined is that one mole of gas will occupy exactly 22.4 litres at standard temperature (0C or 273.15K) and pressure (760 mmHg or 1 atmosphere).

Put them all together, with the constant R, which is dependant on what units you are using, and n, the number of moles, and you can plug into the equation.

The value of R we will use in this case is 0.0821 L atm/mole K

In this case, because you are looking for n, you need to restate the equation by dividing both sides by RT. Now you have n=PV/RT.

pv=nrt

n=pv/rt

n=[(753/760)(.117)/[(.08206 Latm/molK)(...

r = ideal gas constant, and that is .08206 for these units

t = kelvin always, so 85C +273 = K

p = atmospheres, 753/760 = atm

v = liters, .117

n = .00395 moles

.555g/.00395 moles = 140.65 or 141 g/mol with 3 significant figures

Step 2 of 3

Chapter 11, Problem 72P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

This full solution covers the following key subjects: gas, mass, Molar, Find, its. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Since the solution to 72P from 11 chapter was answered, more than 656 students have viewed the full step-by-step answer. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 72P from chapter: 11 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “A sample of gas has a mass of 0.555 g. Its volume is 117 mL at a temperature of 85 °C and a pressure of 753 mm Hg. Find the molar mass of the gas.” is broken down into a number of easy to follow steps, and 35 words.

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A sample of gas has a mass of 0.555 g. Its volume is 117 mL at a temperature of 85 °C