Consider the chemical reaction:2H2O(l) ? 2H2(g) + O2(g)How many moles of H2O are

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

ISBN: 9780321910295 34

Solution for problem 90P Chapter 11

Introductory Chemistry | 5th Edition

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Problem 90P

PROBLEM 90P

Consider the chemical reaction:

2H2O(l) → 2H2(g) + O2(g)

How many moles of H2O are required to form 1.3 L of O2 at 325 K and 0.988 atm?

Step-by-Step Solution:

Step 1 of 3

Solution 90P

Balanced equation:

2H2O(l) → 2H2(g) + O2(g)

2 mol H2O produce 1 mol O2

Use Gas Law Equation to calculate mol of O2

PV = nRT

0.992*1.3 = n * 0.082057*315

n = 1.2896/ 25.848

n = 0.04989 = 0.05 mol O2 produced.

From equation, this will require: 0.05*2 = 0.1mol H2O

If you require the mass of water:

Molar mass H2O = 18g/mol

0.1mol H2O = 18*0.1 = 1.8g H2O required.

Step 2 of 3

Chapter 11, Problem 90P is Solved

Step 3 of 3

Textbook: Introductory Chemistry

Edition: 5

Author: Nivaldo J Tro

ISBN: 9780321910295

Since the solution to 90P from 11 chapter was answered, more than 1505 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: atm, chemical, consider, form, Moles. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The full step-by-step solution to problem: 90P from chapter: 11 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “Consider the chemical reaction:2H2O(l) ? 2H2(g) + O2(g)How many moles of H2O are required to form 1.3 L of O2 at 325 K and 0.988 atm?” is broken down into a number of easy to follow steps, and 26 words.