×
Log in to StudySoup
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 11 - Problem 92p
Join StudySoup for FREE
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 11 - Problem 92p

Already have an account? Login here
×
Reset your password

Oxygen gas reacts with powdered aluminum according to the reaction:4Al(s) + 3O2(g) ? 2

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 92P Chapter 11

Introductory Chemistry | 5th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

4 5 1 329 Reviews
21
3
Problem 92P

PROBLEM 92P

Oxygen gas reacts with powdered aluminum according to the reaction:

4Al(s) + 3O2(g) → 2 Al2O3(s)

How many liters of O2 gas, measured at 782 mm Hg and 25 °C, are required to completely react with 2.4 mol of Al?

Step-by-Step Solution:
Step 1 of 3

Solution 92P

Oxygen gas reacts with powdered aluminum according to the reaction:

4Al(s) + 3O2(g) → 2Al2O3(s)

Given that

P=782 mm of Hg

Temperature =25 0C

No.of moles of aluminium=2.14

We know that

Formula PV=nRT

3 moles of O2 = 2 m0les of Al2O3.

No.of moles of O2 required to give no.of moles of aluminium.

2.14 moles of Al =2.14 moles of Al *3 moles of O2/2 moles of Al2O3.

=3.12 moles of O2 required .

PV=nRT

=3.12*8.314*25/782 mm of Hg

=0.892 moles of O2 requried for the reaction to complete with 2.14 moles of  Aluminium.

                 

Step 2 of 3

Chapter 11, Problem 92P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

Other solutions

People also purchased

Related chapters

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

Oxygen gas reacts with powdered aluminum according to the reaction:4Al(s) + 3O2(g) ? 2