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Lithium reacts with nitrogen gas according to the reaction:6 Li(s) + N2(g) ? 2

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 96P Chapter 11

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 96P

PROBLEM 96P

Lithium reacts with nitrogen gas according to the reaction:

6 Li(s) + N2(g) → 2 Li3N(s)

How many grams of lithium are required to completely react with 58.5 mL of N2 gas measured at STP?

Step-by-Step Solution:
Step 1 of 3

Solution 96P

Given:-

Volume of N2 is 58.5 ml

We have to calculate the amount of Li requires to complete the reaction.

6Li + N2  ------>  2 Li3N

1mole N2 gas=28g

1mole N2 gas occupies 22.4L at STP

therefore 28g N2= 22.4 L or 22400 ml

Thus 58.5 ml of N2 is,

58.5ml N2  28g/22400 ml  =  0.073 g N2

The atomic weight of Li = 6.94g/m

Hence the amount of Li requires to complete the reaction can be calculated as,

0.073gN2/28g/m6Li/N26.94g/m Li = 0.109g Li

Thus 0.109g Li requires to complete the reaction

Step 2 of 3

Chapter 11, Problem 96P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Lithium reacts with nitrogen gas according to the reaction:6 Li(s) + N2(g) ? 2