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# How many grams of magnesium oxide form when 14.8 L of ISBN: 9780321910295 34

## Solution for problem 98P Chapter 11

Introductory Chemistry | 5th Edition

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Problem 98P

PROBLEM 98P

How many grams of magnesium oxide form when 14.8 L of oxygen gas, measured at STP, completely reacts with magnesium metal according to this reaction?

2 Mg(s) + O2(g) → 2MgO(s)

Step-by-Step Solution:
Step 1 of 3

Solution 98P

Given:

Volume of oxygen = 14.8 L

2 Mg(s) + O2(g) → 2MgO(s)

We will have to find out the mass of MgO formed in the given reaction.

At STP (standard temp and pressure, 0 deg C and 1 atm) 1 mole of any ideal gas occupies a volume of 22.4 L

So moles O2 = volume (L) / 22.4 L/mol

= 14.8 L / 22.4 L mol-1

= 0.6607 mol O2

The balanced equation shows that 1 mole O2 forms with 2 moles MgO

So moles MgO = 2 moles...

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

This full solution covers the following key subjects: magnesium, metal, form, gas, grams. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. Since the solution to 98P from 11 chapter was answered, more than 1290 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 98P from chapter: 11 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The answer to “How many grams of magnesium oxide form when 14.8 L of oxygen gas, measured at STP, completely reacts with magnesium metal according to this reaction?2 Mg(s) + O2(g) ? 2MgO(s)” is broken down into a number of easy to follow steps, and 30 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.

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