PROBLEM 100P

Use the ideal gas law to show that 28.0 g of nitrogen gas and 4.00 g of helium gas occupy the same volume at any temperature and pressure.

Solution 100P

Step 1:

Here, we are going to show that 28.0 g of nitrogen gas and 4.00 g of helium gas occupy the same volume at any temperature and pressure.

Step 1: Calculation of number of moles.

Molar mass of Nitrogen = 28.0 g/mol

Molar mass of Helium = 4.0 g/mol

Thus, we know

No. of mole for Nitrogen gas , n = Mass/molar mass = m/M

= 28.0 g/28.0g mol-1

= 1.0 mol

Similarly,

No. of mole for Helium gas , n = Mass/molar mass = m/M

= 4 g/4.0 g mol-1

= 1.0 mol