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A gaseous compound containing hydrogen and carbon is

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 104P Chapter 11

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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11
5
Problem 104P

PROBLEM 104P

A gaseous compound containing hydrogen and carbon is decomposed and found to contain 85.63% C and 14.37% H by mass. The mass of 258 mL of the gas, measured at STP, is 0.646 g. What is the molecular formula of the compound?

Step-by-Step Solution:

Solution 104P

Here, we are going to find the molecular formula of the given compound.

Step 1:

Molecular formula gives the total number of atoms in a molecule.

Step 2:

In order to determine the whole number ratio of C and H in the formula, the following table is drawn:

Element

%

Relative number of atoms(% / atomic mass)

Simple ratio

Whole number ratio

C

85.63

85.63/12 = 7.14

7.14/7.14 = 1

1

H

14.37

14.37/1 = 14.37

14.37/7.14 = 2.01

2

Hence, empirical formula of the compound is CH2.

Empirical formula mass = (1 x 12) + (2 x 1) = 12 + 2 = 14

Step 3:

Again, from ideal gas equation, we have,

                                pV = nRT        ----(1)

Where, p = pressure

        V = volume of the gas

        n =  number of moles of the gas

        R =  universal gas constant and its value is 0.0821 L atm K-1 mol-1

        T =  temperature

Here, p = 1 atm (STP)

        V = 258 mL = 258 / 1000 L = 0.258 L

        T =  273 K (STP)

Substituting the values in equation (1), we get,

                        n = pV / RT

                                n = (1 atm x 0.258 L) / (273 K x 0.0821 L atm K-1 mol-1)

                                   = (0.258 L atm) / (22.4133 L atm mol-1)

                                n = 0.0115 mol.

 

Step 4 of 6

Chapter 11, Problem 104P is Solved
Step 5 of 6

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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