Solution Found!
Solved: Using the integral of see3 u By reduction formula
Chapter 4, Problem 65E(choose chapter or problem)
Using the integral of \(\sec ^{3} u\) By reduction formula 4 in Section 7.2,
\(\int \sec ^{3} u d u=\frac{1}{2}(\sec u \tan u+\ln |\sec u+\tan u|)+C\).
Graph the following functions and find the area under the curve on the given interval.
\(f(x)=\left(x^{2}-25\right)^{1 / 2}\),[5,10]
Questions & Answers
QUESTION:
Using the integral of \(\sec ^{3} u\) By reduction formula 4 in Section 7.2,
\(\int \sec ^{3} u d u=\frac{1}{2}(\sec u \tan u+\ln |\sec u+\tan u|)+C\).
Graph the following functions and find the area under the curve on the given interval.
\(f(x)=\left(x^{2}-25\right)^{1 / 2}\),[5,10]
ANSWER:Problem 65E
Using the integral of by reduction formula 4 in Section 7.2.
Graph the following functions and find the area under the curve on the given interval.
Solution:-
Step 1
To use the reduction formula of , first we convert the f(x) for which we use the substitution