PROBLEM 49P

How much heat is required to vaporize 33.8 g of water at 100 °C?

Solution 49P

Here, we are going to calculate the amount of heat required to vaporize 33.8 g of water at its boiling point.

Step 1:

Heat of vaporization may be defined as the amount of heat required to convert 1 mole of a liquid to its gaseous state. It is denoted by ΔHvap.

Mathematically, it is given by,

ΔHvap = q / m, where ΔHvap = heat of vaporization

q = heat

m = mass