How much heat is required to vaporize 33.8 g of water at 100 °C?
Here, we are going to calculate the amount of heat required to vaporize 33.8 g of water at its boiling point.
Heat of vaporization may be defined as the amount of heat required to convert 1 mole of a liquid to its gaseous state. It is denoted by ΔHvap.
Mathematically, it is given by,
ΔHvap = q / m, where ΔHvap = heat of vaporization
q = heat
m = mass
Textbook: Introductory Chemistry
Author: Nivaldo J Tro
The answer to “How much heat is required to vaporize 33.8 g of water at 100 °C?” is broken down into a number of easy to follow steps, and 14 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Since the solution to 49P from 12 chapter was answered, more than 1393 students have viewed the full step-by-step answer. This full solution covers the following key subjects: heat, much, required, vaporize, Water. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The full step-by-step solution to problem: 49P from chapter: 12 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.