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How much energy is released when 2.55 kg of diethyl ether

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 60P Chapter 12

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 60P

PROBLEM 60P

How much energy is released when 2.55 kg of diethyl ether freezes?

Step-by-Step Solution:

Solution 60P

Step 1:

Amount of diethyl ether((C2H5)2O)= 2.55 Kg

Energy released when 2.55 kg of diethyl ether freezes = ?

Heat must be removed from the (C2H5)2O to cause it to freeze.

The amount of heat released by freezing 1 mole of water is 7.27 kJ/mol.

Formula to calculate the heat required :

 q = mHf

where, q = heat in kJ,

m = mass(in grams),

Hf = heat of fusion

We have Hf in terms of moles, but the mass is given in Kg. So let’s convert the mass in Kg to g and then find the number of moles for the given amount of (C2H5)2O.

First, let’s convert mass in Kg to g :

                1 kg = 1000g.

Therefore,  2.55 Kg in g will be :

 = 2.55 kg  

 = 2550 g.

Now, let’s find number of moles :

        Number of moles(m) =  

Molar mass of  (C2H5)2O = 74.12 g/mol

        Therefore, number of moles =

                                          = 34.40 moles.

So, number of moles in 2550 g of  (C2H5)2O is 34.40 moles.

Step 2 of 2

Chapter 12, Problem 60P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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