Solution Found!
How much energy is released when 2.55 kg of diethyl ether
Chapter 12, Problem 60P(choose chapter or problem)
How much energy is released when 2.55 kg of diethyl ether freezes?
Questions & Answers
QUESTION:
How much energy is released when 2.55 kg of diethyl ether freezes?
ANSWER:
Solution 60P
Step 1:
Amount of diethyl ether((C2H5)2O)= 2.55 Kg
Energy released when 2.55 kg of diethyl ether freezes = ?
Heat must be removed from the (C2H5)2O to cause it to freeze.
The amount of heat released by freezing 1 mole of water is 7.27 kJ/mol.
Formula to calculate the heat required :
q = mHf
where, q = heat in kJ,
m = mass(in grams),
Hf = heat of fusion
We have Hf in terms of moles, but the mass is given in Kg. So let’s convert the mass in Kg to g and then find the number of moles for the given amount of (C2H5)2O.
First, let’s convert mass in Kg to g :
1 kg = 1000g.
Therefore, 2.55 Kg in g will be :
= 2.55 kg
= 2550 g.
Now, let’s find number of moles :
Number of moles(m) =
Molar mass of (C2H5)2O = 74.12 g/mol
Therefore, number of moles =
= 34.40 moles.
So, number of moles in 2550 g of (C2H5)2O is 34.40 moles.