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An 8.5-g ice cube is placed into 255 g of water. Calculate

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 91P Chapter 12

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 91P

PROBLEM 91P

An 8.5-g ice cube is placed into 255 g of water. Calculate the temperature change in the water upon the complete melting of the ice. Hint: Determine how much heat is absorbed by the melting ice and then use q = mC∆T to calculate the temperature change of the 255 g of water.

Step-by-Step Solution:

Solution 91P

Here, we are going to calculate the temperature change in the water upon the complete melting of ice.

Step 1:

Heat of fusion may be defined as the amount of heat required to convert 1 mole of a solid to its liquid state. It is denoted by ΔHf.

Mathematically, it is given by,

                                         ΔHf = q / m, ----(1)        where  ΔHf = heat of fusion

                                                                              q = heat absorbed

                                                                            m = mass

Step 2:

The heat of fusion of ice is 334 J/g

Given, mass of ice = 8.5 g

Substituting the values in the above equation, we get,

                        334 J/g = q / 8.5 g

                                q = (334 J/g) x 8.5 g

                                    = 2839 J

Thus, amount of heat absorbed by the ice = 2839 J

Step 3 of 4

Chapter 12, Problem 91P is Solved
Step 4 of 4

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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