An 8.5-g ice cube is placed into 255 g of water. Calculate the temperature change in the water upon the complete melting of the ice. Hint: Determine how much heat is absorbed by the melting ice and then use q = mC∆T to calculate the temperature change of the 255 g of water.
Here, we are going to calculate the temperature change in the water upon the complete melting of ice.
Heat of fusion may be defined as the amount of heat required to convert 1 mole of a solid to its liquid state. It is denoted by ΔHf.
Mathematically, it is given by,
ΔHf = q / m, ----(1) where ΔHf = heat of fusion
q = heat absorbed
m = mass
The heat of fusion of ice is 334 J/g
Given, mass of ice = 8.5 g
Substituting the values in the above equation, we get,
334 J/g = q / 8.5 g
q = (334 J/g) x 8.5 g
= 2839 J
Thus, amount of heat absorbed by the ice = 2839 J