PROBLEM 91P

An 8.5-g ice cube is placed into 255 g of water. Calculate the temperature change in the water upon the complete melting of the ice. Hint: Determine how much heat is absorbed by the melting ice and then use q = mC∆T to calculate the temperature change of the 255 g of water.

Solution 91P

Here, we are going to calculate the temperature change in the water upon the complete melting of ice.

Step 1:

Heat of fusion may be defined as the amount of heat required to convert 1 mole of a solid to its liquid state. It is denoted by ΔHf.

Mathematically, it is given by,

ΔHf = q / m, ----(1) where ΔHf = heat of fusion

q = heat absorbed

m = mass

Step 2:

The heat of fusion of ice is 334 J/g

Given, mass of ice = 8.5 g

Substituting the values in the above equation, we get,

334 J/g = q / 8.5 g

q = (334 J/g) x 8.5 g

= 2839 J

Thus, amount of heat absorbed by the ice = 2839 J