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Calculate the molarity of each solution.(a) 1.54 mol of LiCl in 22.2 L of solution(b)

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 60P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 60P

Calculate the molarity of each solution.

(a) 1.54 mol of LiCl in 22.2 L of solution

(b) 0.101 mol of LiNO3 in 6.4 L of solution

(c) 0.0323 mol of glucose in 76.2 mL of solution

Step-by-Step Solution:
Step 1 of 3

Answer :

(a) 1.54 mol of LiCl in 22.2 L of solution.

We know that

Molarity = mass /liters.

               =1.54/22.2 L.

               =0.0693 M.

            (b) 0.101 mol of LiNO3 in 6.4 L of solution

We know that

Molarity = mass /liters.

                =0.101 mol/6.4 L

 ...

Step 2 of 3

Chapter 13, Problem 60P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Calculate the molarity of each solution.(a) 1.54 mol of LiCl in 22.2 L of solution(b)