Calculate the molarity of each solution.

(a) 1.54 mol of LiCl in 22.2 L of solution

(b) 0.101 mol of LiNO3 in 6.4 L of solution

(c) 0.0323 mol of glucose in 76.2 mL of solution

Answer :

(a) 1.54 mol of LiCl in 22.2 L of solution.

We know that

Molarity = mass /liters.

=1.54/22.2 L.

=0.0693 M.

(b) 0.101 mol of LiNO3 in 6.4 L of solution

We know that

Molarity = mass /liters.

=0.101 mol/6.4 L

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