A 205-mL sample of ocean water contains 6.8 g of NaCl. What is the molarity of the solution with respect to NaCl?
Solution 63P :
Amount of solute - NaCl = 6.8 g
Amount of solvent -ocean water = 205-mL
Molarity of the solution with respect to NaCl = ?
Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.
Formula to find the molarity of solution :
Amount of solvent is given in mL, let’s convert to L :
1 L = 1000 mL
Therefore, 205 mL in L will be :
= 0.205 L
We have the amount of solute in g, let’s calculate the number of moles first :
Number of moles (n) =
Molar mass of NaCl = 58.44 g/mol.
Therefore, n =
= 0.116 moles.
Textbook: Introductory Chemistry
Author: Nivaldo J Tro
Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 63P from chapter: 13 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: nacl, respect, contains, Ocean, molarity. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The answer to “A 205-mL sample of ocean water contains 6.8 g of NaCl. What is the molarity of the solution with respect to NaCl?” is broken down into a number of easy to follow steps, and 22 words. Since the solution to 63P from 13 chapter was answered, more than 1085 students have viewed the full step-by-step answer.