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A 205-mL sample of ocean water contains 6.8 g of NaCl.

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 63P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 63P

A 205-mL sample of ocean water contains 6.8 g of NaCl. What is the molarity of the solution with respect to NaCl?

Step-by-Step Solution:

Solution 63P :

Step 1:

Given :

Amount of solute - NaCl = 6.8 g

Amount of solvent -ocean water = 205-mL

Molarity of the solution with respect to NaCl = ?

Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.

Formula to find the molarity of solution :

                Molarity =

Amount of solvent is given in mL, let’s convert to L :

                1 L = 1000 mL

Therefore, 205 mL in L will be :

                

                = 0.205 L

We have the amount of solute in g, let’s calculate the number of moles first :

        Number of moles (n) =

Molar mass of NaCl = 58.44 g/mol.

Therefore, n =

                = 0.116 moles.

Step 2 of 2

Chapter 13, Problem 63P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 63P from chapter: 13 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: nacl, respect, contains, Ocean, molarity. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The answer to “A 205-mL sample of ocean water contains 6.8 g of NaCl. What is the molarity of the solution with respect to NaCl?” is broken down into a number of easy to follow steps, and 22 words. Since the solution to 63P from 13 chapter was answered, more than 1085 students have viewed the full step-by-step answer.

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