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A 205-mL sample of ocean water contains 6.8 g of NaCl.

Chapter 13, Problem 63P

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QUESTION:

A 205-mL sample of ocean water contains 6.8 g of NaCl. What is the molarity of the solution with respect to NaCl?

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QUESTION:

A 205-mL sample of ocean water contains 6.8 g of NaCl. What is the molarity of the solution with respect to NaCl?

ANSWER:

Solution 63P :

Step 1:

Given :

Amount of solute - NaCl = 6.8 g

Amount of solvent -ocean water = 205-mL

Molarity of the solution with respect to NaCl = ?

Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.

Formula to find the molarity of solution :

                Molarity =

Amount of solvent is given in mL, let’s convert to L :

                1 L = 1000 mL

Therefore, 205 mL in L will be :

                

                = 0.205 L

We have the amount of solute in g, let’s calculate the number of moles first :

        Number of moles (n) =

Molar mass of NaCl = 58.44 g/mol.

Therefore, n =

                = 0.116 moles.

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