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Solved: A chemist wants to make 2.5 L of a 0.100 M KCl solution. How much KCl in grams

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 73P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 73P

Problem 73P

A chemist wants to make 2.5 L of a 0.100 M KCl solution. How much KCl in grams should the chemist use?

Step-by-Step Solution:
Step 1 of 3

Solution: here, we are going to calculate the mass of KCl required to make the solution.

Step1:

Molarity(M) is defined as number of moles of solute dissolved in one litre (or one cubic decimetre) of solution.

                                                   Moles of solute

                                Molarity = -------------------------------         ------(1)

                                              Volume of solution in litre

Step2:

In the above problem,

Volume of the KCl solution = 2.5 L

Molarity of the KCl solution = 0.100 M

Substituting the values in equation (1), we get,

                                

0.100 M = moles of KCl / 2.5 L

                    Therefore, moles of KCl = 0.100 M x 2.5 L

= 0.25 mol

Step3:

1 mol KCl = molar mass of KCl

0.25 mol KCl = 0.25 x molar mass of KCl

                     = 0.25 x 74.55 g/mol

                     = 18.64 g.

Thus, the required mass of KCl is 18.64 g.

                                                -------------------------------

 

Step 2 of 3

Chapter 13, Problem 73P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: A chemist wants to make 2.5 L of a 0.100 M KCl solution. How much KCl in grams