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Solved: A laboratory procedure calls for making 500.0 mL of a 1.4 M KNO3 solution. How

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 74P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 74P

A laboratory procedure calls for making 500.0 mL of a 1.4 M \(\mathrm {KNO_3}\) solution. How much \(\mathrm {KNO_3}\) in grams is needed?

Equation Transcription:

Text Transcription:

KNO_3

Step-by-Step Solution:

Q:A laboratory procedure calls for making 500.0 mL of a 1.4 M KNO3 solution. How muchKNO3 in grams is needed Step By Step SolutionStep 1 of 1:Molarity is the number of moles of solute per litre of the solution,Given:Mass of potassium nitrate, KNO = 101.193/molMolarity of KNO = Number of moles of KNO / Volume in kg 3 31.4M = Number of moles of KNO / 0.500kg 3Therefore,

Step 2 of 2

Chapter 13, Problem 74P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Since the solution to 74P from 13 chapter was answered, more than 976 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 74P from chapter: 13 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: kno, making, calls, Laboratory, grams. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The answer to “?A laboratory procedure calls for making 500.0 mL of a 1.4 M \(\mathrm {KNO_3}\) solution. How much \(\mathrm {KNO_3}\) in grams is needed?Equation Transcription:Text Transcription:KNO_3” is broken down into a number of easy to follow steps, and 25 words. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.

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Solved: A laboratory procedure calls for making 500.0 mL of a 1.4 M KNO3 solution. How