To what volume should you dilute 25 mL of a 12 M stock HCl solution to obtain a 0.500 M HCl solution?
Step 1 of 3
Molarity of HCl stock solution - initial concentration (M1) = 12 M
Volume (V1) = 25 mL
Molarity of HCl -final concentration (M2) =0.500 M
Volume (V2) = ?
It is known that the relation between molarity and volume is,
M1V1 = M2V2
Where M1 and V1 are the molarity and volume of the initial concentration of solution and M2, V2 are the molarity and volume of final dilute solution.
Now substitute the values of M1, M2 and V2 , we can get the value of V1
M1V1 = M2V2
12M25 mL = 0.5 M V2
V2 = = 600m L
Thus 600mL of solution is required.
Textbook: Introductory Chemistry
Author: Nivaldo J Tro
This full solution covers the following key subjects: HCL, solution, should, obtain, dilute. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The full step-by-step solution to problem: 85P from chapter: 13 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Since the solution to 85P from 13 chapter was answered, more than 643 students have viewed the full step-by-step answer. The answer to “To what volume should you dilute 25 mL of a 12 M stock HCl solution to obtain a 0.500 M HCl solution?” is broken down into a number of easy to follow steps, and 22 words.