To what volume should you dilute 25 mL of a 12 M stock HCl solution to obtain a 0.500 M HCl solution?

Given:

Molarity of HCl stock solution - initial concentration (M1) = 12 M

Volume (V1) = 25 mL

Molarity of HCl -final concentration (M2) =0.500 M

Volume (V2) = ?

It is known that the relation between molarity and volume is,

M1V1 = M2V2

Where M1 and V1 are the molarity and volume of the initial concentration of solution and M2, V2 are the molarity and volume of final dilute solution.

Now substitute the values of M1, M2 and V2 , we can get the value of V1

M1V1 = M2V2

12M25 mL = 0.5 M V2

V2 = = 600m L

Thus 600mL of solution is required.