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Solved: Determine the volume of 0.150 M NaOH solution required to neutralize each sample

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 89P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 89P

Determine the volume of 0.150 M NaOH solution required to neutralize each sample of hydrochloric acid. The neutralization reaction is:

     \(\mathrm {NaOH}(aq)+\mathrm {HCl}(aq) \longrightarrow \mathrm{H_2O}(l)+\mathrm{NaCl}(aq)\)

(a) 25 mL of a 0.150 M HCl solution

(b) 55 mL of a 0.055 M HCl solution

(c) 175 mL of a 0.885 M HCl solution

Equation Transcription:

Text Transcription:

NaOH(aq)+HCl(aq) rightarrow H_2O(l)+NaCl(aq)

Step-by-Step Solution:
Step 1 of 8

Step1 of 8

Solution: Here, we are going to calculate the volume of NaOH solution required to neutralize the given HCl solutions.

Neutralisation reaction is the reaction between an acid and a base to give salt and water. The neutralization reaction in the given problem is:

                                 

Here, 1 mole of HCl requires 1 mole of NaOH for complete neutralization.

___________________

Step 2 of 8

Chapter 13, Problem 89P is Solved
Step 3 of 8

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: Determine the volume of 0.150 M NaOH solution required to neutralize each sample