Solution Found!
Solved: Determine the volume of 0.150 M NaOH solution required to neutralize each sample
Chapter 13, Problem 89P(choose chapter or problem)
Determine the volume of 0.150 M NaOH solution required to neutralize each sample of hydrochloric acid. The neutralization reaction is:
\(\mathrm {NaOH}(aq)+\mathrm {HCl}(aq) \longrightarrow \mathrm{H_2O}(l)+\mathrm{NaCl}(aq)\)
(a) 25 mL of a 0.150 M HCl solution
(b) 55 mL of a 0.055 M HCl solution
(c) 175 mL of a 0.885 M HCl solution
Equation Transcription:
Text Transcription:
NaOH(aq)+HCl(aq) rightarrow H_2O(l)+NaCl(aq)
Questions & Answers
QUESTION:
Determine the volume of 0.150 M NaOH solution required to neutralize each sample of hydrochloric acid. The neutralization reaction is:
\(\mathrm {NaOH}(aq)+\mathrm {HCl}(aq) \longrightarrow \mathrm{H_2O}(l)+\mathrm{NaCl}(aq)\)
(a) 25 mL of a 0.150 M HCl solution
(b) 55 mL of a 0.055 M HCl solution
(c) 175 mL of a 0.885 M HCl solution
Equation Transcription:
Text Transcription:
NaOH(aq)+HCl(aq) rightarrow H_2O(l)+NaCl(aq)
ANSWER:Step1 of 8
Solution: Here, we are going to calculate the volume of NaOH solution required to neutralize the given HCl solutions.
Neutralisation reaction is the reaction between an acid and a base to give salt and water. The neutralization reaction in the given problem is:
Here, 1 mole of HCl requires 1 mole of NaOH for complete neutralization.
___________________