Determine the volume of 0.225 M KOH solution required to neutralize each sample of sulfuric acid. The neutralization reaction is:
\(\mathrm {H_2SO_4}(aq)+2~\mathrm {KOH}(aq) \longrightarrow \mathrm{K_2SO_4}(aq)+2~\mathrm{H_2O}(l)\)
(a) 45 mL of 0.225 M \(\mathrm {H_2SO_4}\)
(b) 185 mL of 0.125 M \(\mathrm {H_2SO_4}\)
(c) 75 mL of 0.100 M \(\mathrm {H_2SO_4}\)
Equation Transcription:
Text Transcription:
H_2SO_4(aq)+2 KOH(aq) rightarrow K_2SO_4(aq)+2 H_2O(l)
H_2SO_4
Step 1 of 8
Here, we are going to calculate the volume of KOH solution required to neutralize the given H2SO4 solutions.
Neutralisation reaction is the reaction between an acid and a base to give salt and water. The neutralization reaction in the given problem is:
Here, 1 mole of requires 2 moles of KOH for complete neutralization.
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