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Solved: What is the minimum amount of 6.0 M H2SO4 necessary to produce 15.0 g of H2(g)

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 95P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 95P

What is the minimum amount of 6.0 M H2SO4 necessary to produce 15.0 g of H2(g) according to the reaction:

2 Al(s) + 3 H2SO4 (aq) → Al2(SO4)2(aq) + 3 H2(g)

Step-by-Step Solution:
Step 1 of 3

Answer :

2Al(s) + 3H2SO4 (aq) → Al2(SO4)2(aq) + 3 H2(g)

Explanation:

Since you are given grams of H2 it will be easiest to work backwards using the stoichiometry.

Therefore:

15g H2× 1mol H2/2.016g H2 × 3mol H2SO4/2molH2 = 7.44molH2SO4

You could go further in the analysis, but you are given the molarity of the sulfuric acid. That should give you some guidance in the direction to solve this problem.

Therefore, using the M=mol/L equation we can plug in the number and solve for the volume.

6.0L=7.44mol/L = (7.44mol H2SO4)6.0MH2SO4.

=44.64LH2SO4

Step 2 of 3

Chapter 13, Problem 95P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: What is the minimum amount of 6.0 M H2SO4 necessary to produce 15.0 g of H2(g)