> > > > Problem 100P

Calculate the molality of a solution containing 257 g

Problem 100P Chapter 13

Introductory Chemistry | 5th Edition

• 2901 Step-by-step solutions solved by professors and subject experts
• Get 24/7 help from StudySoup virtual teaching assistants

Introductory Chemistry | 5th Edition

4 5 0 248 Reviews
22
3
Problem 100P

Calculate the molality of a solution containing 257 g glucose (C6H12O6) dissolved in 1.62 L of water. (Assume a density of 1.00 g/mL for water.)

Step-by-Step Solution:

Solution 100P :

Step 1:

Here, we have to calculate the molality of each solution :

First, let’s see what is molality :

Molality(m) is a property of a solution and is defined as the number of moles of solute per kilogram of solvent. The SI unit for molality is mol/kg.

Formula to find the molality of solution :

Molality(m) =

Step 2:

Given :

Mass of solute - glucose (C6H12O6)  = 257 g

Mass of solvent - water (H2O) = 1.62 L

(Assume a density of 1.00 g/mL for water.)

We have solute in grams, we need moles of solute to calculate the molality. Hence, first we find the moles of solute from the grams given :

Number of moles(n) =

Molar mass of glucose (C6H12O6) = 180.15 g/mol.

Therefore, n =

n = 1.426 mol

We need mass of solvent in Kg, to calculate molality, hence let’s convert mass of water in L to Kg :

1 L = 1 Kg

Therefore, 1.62 L of water in Kg will be 1.62 Kg

Step 3 of 3

ISBN: 9780321910295

This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: Water, Dissolved, containing, Density, calculate. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. Since the solution to 100P from 13 chapter was answered, more than 504 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 100P from chapter: 13 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The answer to “Calculate the molality of a solution containing 257 g glucose (C6H12O6) dissolved in 1.62 L of water. (Assume a density of 1.00 g/mL for water.)” is broken down into a number of easy to follow steps, and 25 words.

Related chapters

Unlock Textbook Solution

Calculate the molality of a solution containing 257 g

×
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 13 - Problem 100p

Get Full Access to Introductory Chemistry - 5 Edition - Chapter 13 - Problem 100p

I don't want to reset my password

Need help? Contact support

Need an Account? Is not associated with an account
We're here to help