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Solved: Calculate the molality of a solution containing 257 g glucose (C6H12O6)
Chapter 13, Problem 100P(choose chapter or problem)
Calculate the molality of a solution containing 257 g glucose \(\mathrm {(C_6H_{12}O_6)}\) dissolved in 1.62 L of water. (Assume a density of 1.00 g/mL for water.)
Questions & Answers
QUESTION:
Calculate the molality of a solution containing 257 g glucose \(\mathrm {(C_6H_{12}O_6)}\) dissolved in 1.62 L of water. (Assume a density of 1.00 g/mL for water.)
ANSWER:Step 1 of 3
Here, we have to calculate the molality of each solution :
First, let’s see what is molality :
Molality(m) is a property of a solution and is defined as the number of moles of solute per kilogram of solvent. The SI unit for molality is mol/kg.
Formula to find the molality of solution :
\(\text { Molality }(\mathrm{m})=\frac{\text { moles of Solute }}{\text { mass of Solvent }(\text { in } K g)}\)