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Solved: A glucose solution contains 55.8 g of glucose (C6H12O6) in 455 g of water

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 105P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 105P

Problem 105P

A glucose solution contains 55.8 g of glucose (C6H12O6) in 455 g of water. Calculate the freezing point and boiling point of the solution. (Assume a density of 1.00 g/mL for water.)

Step-by-Step Solution:

Solution 105 P:

Here, we are going to calculate the boiling point and freezing point of the solution .

Step 1: Calculation of the amount of glucose in mol

We know,

Molar mass of glucose = 180.15 g/mol

Mass of glucose = 55.8 g

Amount of glucose in mol = 55.8 g/180.1559 g/mol = 0.3097 mol

 

Step 2 of 3

Chapter 13, Problem 105P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: A glucose solution contains 55.8 g of glucose (C6H12O6) in 455 g of water