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Solved: A glucose solution contains 55.8 g of glucose (C6H12O6) in 455 g of water
Chapter 13, Problem 105P(choose chapter or problem)
A glucose solution contains 55.8 g of glucose \(\mathrm {(C_6H_{12}O_6)}\) in 455 g of water. Calculate the freezing point and boiling point of the solution. (Assume a density of 1.00 g/mL for water.)
Equation Transcription:
Text Transcription:
(C_6H_{12}O_6)
Questions & Answers
QUESTION:
A glucose solution contains 55.8 g of glucose \(\mathrm {(C_6H_{12}O_6)}\) in 455 g of water. Calculate the freezing point and boiling point of the solution. (Assume a density of 1.00 g/mL for water.)
Equation Transcription:
Text Transcription:
(C_6H_{12}O_6)
ANSWER:Solution 105 P:
Here, we are going to calculate the boiling point and freezing point of the solution .
Step 1: Calculation of the amount of glucose in mol
We know,
Molar mass of glucose = 180.15 g/mol
Mass of glucose = 55.8 g
Amount of glucose in mol = 55.8 g/180.1559 g/mol = 0.3097 mol