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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 13 - Problem 106p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 13 - Problem 106p

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# Solved: An ethylene glycol solution contains 21.2 g of ethylene glycol (C2H6O2) in 85.4 ISBN: 9780321910295 34

## Solution for problem 106P Chapter 13

Introductory Chemistry | 5th Edition

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Problem 106P

Problem 106P

An ethylene glycol solution contains 21.2 g of ethylene glycol (C2H6O2) in 85.4 mL of water. Calculate the freezing point and boiling point of the solution. (Assume a density of 1.00 g/mL for water.)

Step-by-Step Solution:

Solution 106P:

Here, we are going to calculate the boiling point and freezing point of the solution .

Step 1: Calculation of the amount of ethylene glycol in mol

Mass of water = Density x volume = 1.0 g/L x 85.4 L = 85.4 g

We know,

Molar mass of ethylene glycol  = 62.07 g/mol

Mass of ethylene glycol  = 21.2 g

Amount of glucose in mol = 21.2 g/62.07 g/mol = 0.3415 mol

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The answer to “An ethylene glycol solution contains 21.2 g of ethylene glycol (C2H6O2) in 85.4 mL of water. Calculate the freezing point and boiling point of the solution. (Assume a density of 1.00 g/mL for water.)” is broken down into a number of easy to follow steps, and 34 words. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 106P from 13 chapter was answered, more than 4201 students have viewed the full step-by-step answer. This full solution covers the following key subjects: Water, solution, point, glycol, Ethylene. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The full step-by-step solution to problem: 106P from chapter: 13 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM.

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