Hydrochloric acid is usually purchased in concentrated form with a 37.0% HCl concentration by mass and a density of 1.20 g/mL. How much of the concentrated stock solution in milliliters should you use to make 2.5 L of 0.500 M HCl?
You should use 97 ml of the stock solution and make it up to a volume of 2.5LExplanation:
You need 2.5L of 0.5M HCl solution.
C = nV
n = CV
So the no. moles HCl required = 2.5×0.5=1.25
Now we need to find how many grams this is. We get this by multiplying by the weight of 1 mole of HCl which is equal to its Mr (mass required) in grams.
So mass required = 1.25×34.46=43.07g
We know that the concentrated form is 37.0% by mass.
This means that 100g of this concentrated solution contains...