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Answer: An aqueous solution containing 35.9 g of an unknown molecular (nonelectrolyte)

Chapter 13, Problem 126P

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QUESTION:

An aqueous solution containing 35.9 g of an unknown molecular (nonelectrolyte) compound in 150.0 g of water has a freezing point of \(\mathrm{-1.3~^\circ C}\). Calculate the molar mass of the unknown compound.

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QUESTION:

An aqueous solution containing 35.9 g of an unknown molecular (nonelectrolyte) compound in 150.0 g of water has a freezing point of \(\mathrm{-1.3~^\circ C}\). Calculate the molar mass of the unknown compound.

ANSWER:

Solution: Here, we are going to calculate the molar mass of the unknown compound.

Step1:

The freezing point of a substance may be defined as the temperature at which the vapour pressure of the substance in its liquid phase is equal to its vapour pressure in the solid phase.

In order to determine the molar mass of the solute, te following expression can be used:

                                        Kf x w2 x 1000

M2 = ------------------------        -----(1)

            ΔTf x w1

Where, M2 = molar mass of the solute

Kf = freezing point depression constant

w2 = given mass of solute in grams

ΔT

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