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What happens to [OH?] in an aqueous solution when [H3O+]

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 22Q Chapter 14

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 22Q

What happens to [OH−] in an aqueous solution when [H3O+] increases?

Step-by-Step Solution:
Step 1 of 3

Decreases

Explanation:

The concentration of [OH-] ion decreases when [H3O]+ ion concentration increases. This is because the dissociation constant or ionization constant is constant. The relation between[OH-] ion and   [H3O]+ ion is Kw = [H3O]+[OH-]

                                               =(1.0 10-7) (1.010-7)

                                         ...

Step 2 of 3

Chapter 14, Problem 22Q is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

The answer to “What happens to [OH?] in an aqueous solution when [H3O+] increases?” is broken down into a number of easy to follow steps, and 11 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: aqueous, happens, increases, solution. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The full step-by-step solution to problem: 22Q from chapter: 14 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 22Q from 14 chapter was answered, more than 297 students have viewed the full step-by-step answer. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.

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