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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 14 - Problem 26q
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 14 - Problem 26q

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# In any aqueous solution at 25 °C, the sum of pH and pOH is 14.0. Explain why this is so

ISBN: 9780321910295 34

## Solution for problem 26Q Chapter 14

Introductory Chemistry | 5th Edition

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Problem 26Q

In any aqueous solution at $$\mathrm{25~^\circ C}$$, the sum of pH and pOH is 14.0. Explain why this is so.

Equation Transcription:

Text Transcription:

25 ^oC

Step-by-Step Solution:

Solution 26Q:

Here, we are going to derive the the sum of pH and pOH is 14.0 at 25 °C.

Step 1:

Water is amphoteric which  can act as either an acid or a base. Pure water can behave as an acid and base with itself. Thus the process is called autoionization.So, we can write,

H2O (l) --------> H+ (aq) + OH-(aq)

The Equilibrium constant  for the reaction is

Kw = [H+(aq)][OH-(aq)]------(1)

where Kw is known as ion product constant for water and at 25oC.

For pure water, at  25oC,  Kw = 1.0 x 10-14

Therefore, equation (1) ,

1.0 x 10-14 =  [H+][OH-]------(2)

Step 2 of 3

Step 3 of 3

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