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In any aqueous solution at 25 °C, the sum of pH and pOH is

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 26Q Chapter 14

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 26Q

In any aqueous solution at 25 °C, the sum of pH and pOH is 14.0. Explain why this is so.

Step-by-Step Solution:

Solution 26Q:

Here, we are going to derive the the sum of pH and pOH is 14.0 at 25 °C.

Step 1:

Water is amphoteric which  can act as either an acid or a base. Pure water can behave as an acid and base with itself. Thus the process is called autoionization.So, we can write,

H2O (l) --------> H+ (aq) + OH-(aq)

The Equilibrium constant  for the reaction is

Kw = [H+(aq)][OH-(aq)]------(1)

where Kw is known as ion product constant for water and at 25oC.

For pure water, at  25oC,  Kw = 1.0 x 10-14

Therefore, equation (1) ,

1.0 x 10-14 =  [H+][OH-]------(2)

Step 2:

pH and pOH is defined as

pH= -log[H+]

pOH= -log[OH-]

From equation (2)

1.0 x 10-14 =  [H+][OH-]------(2)

Taking log on both sides of equation ?(2),

-log(1.0 x 10-14) = -log[H+]- log[OH-]

10-14 = pH + pOH

pH + pOH =14

Step 3 of 3

Chapter 14, Problem 26Q is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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